(16/49)-v^2=0

Solution for (16/49)-v^2=0 equation:

(16/49)-v^2=0

We add all the numbers together, and all the variables

-v^2+(+16/49)=0

We add all the numbers together, and all the variables

-1v^2+(+16/49)=0

We get rid of parentheses

-1v^2+16/49=0

We multiply all the terms by the denominator


-1v^2*49+16=0

Wy multiply elements

-49v^2+16=0

a = -49; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-49)·16
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56}{2*-49}=\frac{-56}{-98}
=4/7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56}{2*-49}=\frac{56}{-98}
=-4/7
$